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THE BRIGHT SIDE OF HARDNESS in .NET Get 39 barcode in .NET THE BRIGHT SIDE OF HARDNESS




How to generate, print barcode using .NET, Java sdk library control with example project source code free download:
THE BRIGHT SIDE OF HARDNESS using barcode maker for .net control to generate, create code 3 of 9 image in .net applications. UPC Case Code De nition 7.17 (ef VS .NET Code39 cient codes supporting implicit decoding): For xed functions q, : N N and : N (0, 1], the mapping : {0, 1} {0, 1} is said to be ef cient and supports implicit decoding with parameters q, , if it satis es the following two conditions: 1.

Encoding (or ef ciency): The mapping is polynomial-time computable. It is instructive to view as mapping N -bit long strings to sequences of length (N ) over [q(N )], and to view each (codeword) (x) [q(. x. )] (. x. ) as a mapping from [ (. x. )] to [q(. x. )]. 2. Decoding (i VS .

NET bar code 39 n implicit form): There exists a polynomial p such that the following holds. For every w : [ (N )] [q(N )] and every x {0, 1} N such that (x) is (1 (N ))-close to w, there exists an oracle-aided19 circuit C of size p((log N )/ (N )) such that, for every i [N ], it holds that C w (i) equals the i th bit of x. The encoding condition implies that is polynomially bounded.

The decoding condition refers to any -codeword that agrees with the oracle w : [ (N )] [q(N )] on an (N ) fraction of the (N ) coordinates, where (N ) may be very small. We highlight the nontriviality of the decoding condition: There are N bits of information in x, while the circuit C may encode only p((log N )/ (N )) bits of information about x. Thus, x is (implicitly) recovered by C based mainly on a highly corrupted version of (x).

Furthermore, each desired bit of x is recovered (by C) by making at most p((log N )/ (N )) queries to this corrupted version of (x). We mention that the foregoing decoding condition is related to list decoding (as de ned in Appendix E.1.

1).20 Let us now relate the transformation of f n to f n , which underlies Proposition 7.16, to De nition 7.

17. We view f n as a binary string of length N = 2n (representing the truth table m 3 of f n : H m {0, 1}) and analogously view f n : F m F as an element of F . F. = F N (or as a ma VS .NET Code 39 Extended pping from [N 3 ] to [. F. ]).21 Recall that .net framework Code 39 Full ASCII the transformation of f n to f n is ef cient.

We mention that this transformation also supports implicit decoding with parameters q, , such that (N ) = N 3 , (N ) = (n), and q(N ) = (n/ (n))3 , where N = 2n . The latter fact is highly non-trivial, but establishing it is beyond the scope of the current text (and the interested reader is referred to [218]). We mention that the transformation of f n to f n enjoys additional features, which are not required in De nition 7.

17 and will not be used in the current context. For example, there are at most O(1/ (2n )2 ) codewords (i.e.

, f n s) that are (1 (2n ))-close to any xed w : [ (2n )] [q(2n )], and the corresponding oracle-aided circuits can. Oracle-aided circu its are de ned analogously to oracle Turing machines. Alternatively, we may consider here oracle machines that take advice such that both the advice length and the machine s running time are upper-bounded by p((log N )/ (N )). The relevant oracles may be viewed either as blocks of binary strings that encode sequences over [q(N )] or as sequences over [q(N )].

Indeed, in the latter case we consider non-binary oracles, which return elements in [q(N )]. 20 Recall that, on input w [q(N )] (N ) , a list-decoding algorithm for : {0, 1} N [q(N )] (N ) is required to output the list L w containing every string x {0, 1} N such that (x) agrees with w on (N ) fraction of the locations. Turning to the foregoing decoding condition (of De nition 7.

17), note that it requires outputting (bits of) one speci c string x L w . This can be obtained by hard-wiring (in the list-decoding circuit) the index of x in L w , while taking advantage of the fact that the circuit may depend on x and w. Note, however, that the circuit obtained in this way may not satisfy the stringent decoding condition of De nition 7.

17, which requires a circuit of p((log N )/ (N ))-size. On the other hand, the decoding condition does not refer to the complexity of obtaining the aforementioned oracle-aided circuits (and, in particular, may not yield a list-decoding algorithm). 21 Recall that N = 2n = .

H . m and F. = . H . 3 . Hence, . F. m = N 3 .
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